2009
DOI: 10.1137/s0040585x97983778
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The Shepp–Shiryaev Stochastic Game Driven by a Spectrally Negative Lévy Process

Abstract: This document is the author's final manuscript accepted version of the journal article, incorporating any revisions agreed during the peer review process. Some differences between this version and the published version may remain. You are advised to consult the publisher's version if you wish to cite from it.The Shepp-Shiryaev stochastic game driven by a spectrally negative Lévy process.

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Cited by 32 publications
(57 citation statements)
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“…Then, we put y 0 (s) = s and define a decreasing sequence ( y n (s)) n∈N such that y 2l−1 (s) = sup{y < y 2l−2 (s) | b * (s, y) > s} and y 2l (s) = sup{y < y 2l−1 (s) | b * (s, y) ≤ s}, whenever they exist, and put y 2l−1 (s) = y 2l (s) = 0, l ∈ N, otherwise. Moreover, we can also define a decreasing sequence ( y n (s)) n∈N such that the boundary b * (s, y) exits the region E 3 from the side of d 3 2 at the points (s − y 2k−1 (s), s, y 2k−1 (s)) and enters E 3 downwards at the points (s − y 2k (s), s, y 2k (s)). Namely, we put y 0 (s) = s and define y 2k−1 (s) = sup{y < y 2k−2 (s) | b * (s, y) < s − y} and y 2k (s) = sup{y < y 2k−1 (s) | b * (s, y) ≥ s − y}, whenever such points exist, and put y 2k−1 (s) = y 2k (s) = 0 otherwise, for k ∈ N. Note that 0 < y 2k (s) < y 2k−1 (s) < s − K , k ∈ N, by construction.…”
Section: Solution Of the Free-boundary Problemmentioning
confidence: 99%
See 3 more Smart Citations
“…Then, we put y 0 (s) = s and define a decreasing sequence ( y n (s)) n∈N such that y 2l−1 (s) = sup{y < y 2l−2 (s) | b * (s, y) > s} and y 2l (s) = sup{y < y 2l−1 (s) | b * (s, y) ≤ s}, whenever they exist, and put y 2l−1 (s) = y 2l (s) = 0, l ∈ N, otherwise. Moreover, we can also define a decreasing sequence ( y n (s)) n∈N such that the boundary b * (s, y) exits the region E 3 from the side of d 3 2 at the points (s − y 2k−1 (s), s, y 2k−1 (s)) and enters E 3 downwards at the points (s − y 2k (s), s, y 2k (s)). Namely, we put y 0 (s) = s and define y 2k−1 (s) = sup{y < y 2k−2 (s) | b * (s, y) < s − y} and y 2k (s) = sup{y < y 2k−1 (s) | b * (s, y) ≥ s − y}, whenever such points exist, and put y 2k−1 (s) = y 2k (s) = 0 otherwise, for k ∈ N. Note that 0 < y 2k (s) < y 2k−1 (s) < s − K , k ∈ N, by construction.…”
Section: Solution Of the Free-boundary Problemmentioning
confidence: 99%
“…In addition, the process (X, S, Y ) can exit the region R 3 2l in (3.30) passing to the stopping region D * from (2.9) only through the point (s(y), s(y), y), by hitting the plane d 3 1 , so that increasing its second component S until it reaches the value s(y) = inf{q > s | b * (q, y) ≤ q}. Observe that the boundary b * (q, y) provides the unique solution of the equation in (3.26) with the starting value b * (q, q−) = h * (q), for each q ≤ s(y), given that this solution stays strictly above the surface x = K ∨ (rK/δ(q, y)).…”
Section: Solution Of the Free-boundary Problemmentioning
confidence: 99%
See 2 more Smart Citations
“…For other examples of stochastic games, see e.g. Kifer [12], Kyprianou [14], Baurdoux and Kyprianou [3], Gapeev and Kühn [10], Baurdoux et al [4]. Note that the McKean game can be seen as an extension of the classic McKean optimal stopping problem (cf.…”
Section: Introductionmentioning
confidence: 99%