2016
DOI: 10.48550/arxiv.1607.00049
|View full text |Cite
Preprint
|
Sign up to set email alerts
|

The Steinhaus-Weil property: its converse, subcontinuity and Solecki amenability

Abstract: The Steinhaus-Weil theorem that concerns us here is the simple, or classical, 'interior-points' property -that in a Polish topological group a nonnegligible set B has the identity as an interior point of B −1 B. There are various converses; the one that mainly concerns us is due to Simmons and Mospan. Here the group is locally compact, so we have a Haar reference measure η. The Simmons-Mospan theorem states that a (regular Borel) measure has such a Steinhaus-Weil property if and only if it is absolutely contin… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1

Citation Types

0
1
0

Year Published

2021
2021
2021
2021

Publication Types

Select...
1

Relationship

1
0

Authors

Journals

citations
Cited by 1 publication
(1 citation statement)
references
References 85 publications
(70 reference statements)
0
1
0
Order By: Relevance
“…The two particular cases asserted follow from the Interior-point Theorem for category (Steinhaus-Piccard-Pettis theorem [Oxt,Th. 4.8] or [BinO2]): indeed, G S , as an open subset of a Banach space, is analytic, so S(G S ), being the continuous image of an analytic set, is analytic, so has the Baire property, by Nikodym's theorem [Rog]. So 1 A ∈ int(S(G S )S(G S ) −1 )⊆S(G S ), the latter inclusion holding because S(G S ) is a group.…”
Section: S(w(s) + W(t)s(w(s)) = S(w(s) • S W(t)) = S(w(s))s(w(t))mentioning
confidence: 99%
“…The two particular cases asserted follow from the Interior-point Theorem for category (Steinhaus-Piccard-Pettis theorem [Oxt,Th. 4.8] or [BinO2]): indeed, G S , as an open subset of a Banach space, is analytic, so S(G S ), being the continuous image of an analytic set, is analytic, so has the Baire property, by Nikodym's theorem [Rog]. So 1 A ∈ int(S(G S )S(G S ) −1 )⊆S(G S ), the latter inclusion holding because S(G S ) is a group.…”
Section: S(w(s) + W(t)s(w(s)) = S(w(s) • S W(t)) = S(w(s))s(w(t))mentioning
confidence: 99%