“…Using the integration by parts formula and condition ( 1.1 ), we have Now take the first and the second integrals on the right-hand side of the latter expression. Using the integration by parts formula and making use of condition ( 1.1 ), we get Proceeding in the similar way and using condition ( 1.1 ) and the definition of weight function, we obtain Now we take Using Theorem 2.1 from [ 16 ], we have Now, using (2.6) of [ 15 ], we have Substituting ( 3.12 ) and ( 3.13 ) in ( 3.11 ), we have Here, Using the above conditions, we obtain Using the integration by parts formula, we obtain …”