2001
DOI: 10.1021/ja0106927
|View full text |Cite
|
Sign up to set email alerts
|

Theoretical, Thermodynamic, Spectroscopic, and Structural Studies of the Consequences of One-Electron Oxidation on the Fe−X Bonds in 17- and 18-Electron Cp*Fe(dppe)X Complexes (X = F, Cl, Br, I, H, CH3)

Abstract: The compounds Cp*Fe(dppe)X ([Fe]X) and the corresponding cation radicals [Fe*]X*+ are available for the series X = F, Cl, Br, I, H, CH3. This has allowed for a detailed investigation of the dependence of the nature of Fe-X bonding on the identity of X and the oxidation state (charge) of the complex. Cyclic voltammetry demonstrates that the electrode potentials for the [Fe]X0/+ couples decrease in the order I > Br > Cl > H > F > CH3. An "inverse halide order" is seen, in which the most electronegative X leads t… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

11
75
1

Year Published

2002
2002
2019
2019

Publication Types

Select...
8
1

Relationship

1
8

Authors

Journals

citations
Cited by 94 publications
(87 citation statements)
references
References 110 publications
11
75
1
Order By: Relevance
“…The reactivity of 18-electron halo complexes towards protonation in [MX(Cp)(PR 3 ) 2 ] (M Ru or Os; R Me or Ph; X Cl, Br, or I) [34] has been attributed to the increase of the p-p 4-electron repulsion in the series I < Br < Cl [11] 1 ). As in the case of trans-[IrX(CO)(PR 3 ) 2 ] [26], the bottom line is that fluoride acts as a negative point charge located close to the metal and destabilizes the metal orbitals, including those with p-symmetry [35]. Again, the fluoro complex is the most easily oxidized in the halide series, which is accurately reproduced by the energy ordering of the HOMOs, with the fluoro complex having the most destabilized one.…”
Section: Fig 4 Push-pull Interactionmentioning
confidence: 81%
“…The reactivity of 18-electron halo complexes towards protonation in [MX(Cp)(PR 3 ) 2 ] (M Ru or Os; R Me or Ph; X Cl, Br, or I) [34] has been attributed to the increase of the p-p 4-electron repulsion in the series I < Br < Cl [11] 1 ). As in the case of trans-[IrX(CO)(PR 3 ) 2 ] [26], the bottom line is that fluoride acts as a negative point charge located close to the metal and destabilizes the metal orbitals, including those with p-symmetry [35]. Again, the fluoro complex is the most easily oxidized in the halide series, which is accurately reproduced by the energy ordering of the HOMOs, with the fluoro complex having the most destabilized one.…”
Section: Fig 4 Push-pull Interactionmentioning
confidence: 81%
“…ΔZPVE is the zero point vibrational energy change obtained from vibrational frequency calculations. Δ E th is the change associated with the translational (3 RT /2), rotational (3 RT /2), and vibrational energy in going from 0 to 298 K. Δ( PV ) is the molar work, which is equal to Δ n RT, assuming the ideal gas behavior 3, 36, 37, 43–50…”
Section: Theoretical Methodsmentioning
confidence: 99%
“…61,62 Indeed, the oxidation of metal hydrides causes large increases in acidity, as the reductive elimination of H + is certainly more favorable when the metal site is more electron poor. One family of species for which the thermodynamics are well studied are the bis(diphosphine) complexes of Ni.…”
Section: Formation and Characterization Of Metal Hydridesmentioning
confidence: 99%