“…For example, Sn(HPO 4 ) 2 was formed after calcined at 250 °C for 8 h and further increase of heat treatment time will dehydrate Sn(HPO 4 ) 2 , forming SnP 2 O 7 (Figure 1d). [
28 ] Therefore, the reaction of SnO 2 , TiO 2 , and ZrO 2 with PA start from the formation of M(HPO 4 ) 2 (M = Sn, Ti, and Zr) intermediates at lower temperature, which will gradually dehydrate to form MP 2 O 7 with the increased temperature and duration. This can be shown in the following reaction steps:
…”