“…0 5 15 min(M, R), 0 5 k 5 N -I , ( " ) q;'+'-'(l -ql)'S(c, In, M -i , R -i ) (7)where a = k -j + e, and q1 = *, L being the packet length, and S(c, In, M , R) is given by(3).Let P = (Pij f k ) be the probability transition matrix and ll = { r i j } den'ote the steady-The system throughput 81, which is defined as the average number of packets transmitted per chip time, can be obtained as follows:el = C(N -i -j ) A T i j .The channel throughput (defined as the average number of packets transmitted per slot per channel) is given by81 L e, = -M noting that there are L chip times per packet. vious sections and is given by, in chip times, The packet delay is obtained similarly as in the pre-E ( D ) = -N 1 --el A + ' .…”