1981
DOI: 10.1088/0022-3719/14/20/016
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Time-dependent correlations of the one-dimensional isotropic XY model

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Cited by 43 publications
(40 citation statements)
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“…Close to this point quantum critical scaling is expected [3] and the system goes to a free fermion fixed point [39]. This allows us to use a Fredholm determinant technique to compute the scaling function exactly [40][41][42]. In addition to this universal scaling part, the nonuniversal part includes a robust thermally activated longitudinal mode, which remains visible and underdamped across the entire Brillouin zone and in an energy range far exceeding the temperature scale.…”
Section: Introductionmentioning
confidence: 99%
“…Close to this point quantum critical scaling is expected [3] and the system goes to a free fermion fixed point [39]. This allows us to use a Fredholm determinant technique to compute the scaling function exactly [40][41][42]. In addition to this universal scaling part, the nonuniversal part includes a robust thermally activated longitudinal mode, which remains visible and underdamped across the entire Brillouin zone and in an energy range far exceeding the temperature scale.…”
Section: Introductionmentioning
confidence: 99%
“…3). In particular, the transfer between spins 1 and 2 is quenched if D 13 and D 23 have opposite signs and ͉D 13 ͉ Ϸ ͉D 23 ͉ Ͼ ͉D 12 ͉. This is the case for the transfer shown in Fig.…”
Section: Transfer Efficiencymentioning
confidence: 91%
“…As expected, the transfer efficiency can be either positive or negative. Note that in contrast to the transfer of z magnetization, significant transfer of x magnetization occurs if D 13 and D 23 have opposite signs and ͉D 13 ͉ Ϸ ͉D 23 ͉ Ͼ ͉D 12 ͉. Hence, in some cases, the quenching of polarization transfer can be circumvented by transferring x rather than z magnetization.…”
Section: Transfer Efficiencymentioning
confidence: 99%
“…Let us consider the strong-field zero temperature case |Ω | > |J| and β → ∞ when the dynamic structure factorsS αβ (κ, ω) are as follows:S xx (κ, ω) = isgn(Ω )S xy (κ, ω) = (π/2)δ(ω − |Ω | − J cos κ) [4]. As a result, after some calcula-tions we find…”
Section: Theorymentioning
confidence: 99%
“…S xx (κ, ω) for 1/2 ≤ p ≤ 1 follows from (6) after the change κ → κ ∓ π. Equation (6) contains the above-mentioned exact result [4] in the nonrandom limit ξ → ∞ (when p = 0 or p = 1). In the opposite limit of strong disorder ξ = 0 (when p = 1/2) the right hand side of (6) transforms into…”
Section: Theorymentioning
confidence: 99%