“…and the position vector is written rtj = iy(sin 0 cos sin £2 sin i/', cos £2) (15) The dot product of these two vectors simplifies to s-ry = s/y[sin(0/2) cos £2 -cos(0/2) sin £2 cos($ -f)] (16) To determine Fy, the scattering function eis''u must be integrated over the surface of the sphere defined by £2 and \p. The anisotropic spatial orientation is included by multiplying the scattering function with an appropriate distribution function, F(£2,^), before integration Fy(s) = Sin £2d^d £2 (17) Mathematical details on the evaluation of this integral for several relevant distribution functions have been consigned to the Appendix, For the case of an isotropic distribution (P(Q,\p) = 1), the results is:…”