2019
DOI: 10.1142/s0129167x20500032
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Topological generation results for free unitary and orthogonal groups

Abstract: We show that for every N ≥ 3 the free unitary group U + N is topologically generated by its classical counterpart U N and the lower-rank U + N −1 . This allows for a uniform inductive proof that a number of finiteness properties, known to hold for all N = 3, also hold at N = 3. Specifically, all discrete quantum duals U + N and O + N are residually finite, and hence also have the Kirchberg factorization property and are hyperlinear. As another consequence, U + N are topologically generated by U N and their max… Show more

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Cited by 9 publications
(23 citation statements)
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“…can be proved by recurrence on N. Indeed, at N = 1 there is nothing to prove, at N = 2 this is something well-known, and elementary, as explained for instance in [44], [46], and in general, the recurrence step N − 1 → N can be established as follows:…”
Section: Quantum Groupsmentioning
confidence: 97%
See 2 more Smart Citations
“…can be proved by recurrence on N. Indeed, at N = 1 there is nothing to prove, at N = 2 this is something well-known, and elementary, as explained for instance in [44], [46], and in general, the recurrence step N − 1 → N can be established as follows:…”
Section: Quantum Groupsmentioning
confidence: 97%
“…We will need the following key result, coming from [39], [44], [46]: Theorem 2.24. The following happen:…”
Section: Quantum Groupsmentioning
confidence: 99%
See 1 more Smart Citation
“…(2) B + N , C + N are Fourier liberations too, by using a Fourier transform. (3) S + N is a Fourier liberation too, being generated by its tori [39], [43]. (4) H + N , K + N remain to be investigated, by using the general theory in [78].…”
Section: Orbits Orbitalsmentioning
confidence: 99%
“…Generally speaking, this is something quite difficult, because for the empty graph itself we are in need of the above-mentioned technical results from [39], [43].…”
Section: Orbits Orbitalsmentioning
confidence: 99%