“…from which using the group multiplication we can determine the permutation representation of all other group elements. Now we choose the three twist operators to be charged under the group elements a, a 3 b 3 , b which determines the monodromies: σ a (x 1 ) : (1, 2, 3, 4) (5,6,7,8) (9,10,11,12) (13,14,15,16) , 6,13,11) (2,7,14,12) (3,8,15,9) (4,5,16,10) , (2,11,16,8) (3,12,13,5) (4,9,14,6) . (33) Each twist operator has a cycle structure consisting of four cycles of length four.…”