2009
DOI: 10.1016/j.jnt.2009.01.008
|View full text |Cite|
|
Sign up to set email alerts
|

Transcendence of the log gamma function and some discrete periods

Abstract: We study transcendental values of the logarithm of the gamma function. For instance, we show that for any rational number xtranscendental with at most one possible exception. Assuming Schanuel's conjecture, this possible exception can be ruled out. Further, we derive a variety of results on the Γ -function as well as the transcendence of certain series of the form ∞ n=1 P (n)/Q (n), where P (x) and Q (x) are polynomials with algebraic coefficients.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

1
15
0

Year Published

2009
2009
2022
2022

Publication Types

Select...
6

Relationship

4
2

Authors

Journals

citations
Cited by 9 publications
(16 citation statements)
references
References 10 publications
1
15
0
Order By: Relevance
“…This forces that d a = 0 for all a since ξ a 's are multiplicatively independent. Again going back to (5) and following the same argument, we get e b = 0, f c = 0 for all b, c. This completes the proof.…”
Section: Proof Of Theorem 12supporting
confidence: 61%
“…This forces that d a = 0 for all a since ξ a 's are multiplicatively independent. Again going back to (5) and following the same argument, we get e b = 0, f c = 0 for all b, c. This completes the proof.…”
Section: Proof Of Theorem 12supporting
confidence: 61%
“…It has been established in [10] that if we assume the conjecture of Schanuel, log π is not a Baker period. Thus, we see that in the proof of Theorem 3, the term q/2 a=1 (a,p)=1 c a log π = q/2 a=1 (a,p)=1 c a log sin πa q is necessarily equal to zero when the coefficients c a are algebraic numbers.…”
Section: Discussionmentioning
confidence: 99%
“…The notion of periods has been introduced by Kontsevich and Zagier [11] and these Baker periods are examples of transcendental periods. As mentioned by the authors, the co-primality condition cannot be dispensed with in their conjecture as illustrated by the following example:…”
Section: )mentioning
confidence: 99%
“…We shall need the following consequence of the above conjecture which is not difficult to deduce. This was done in an earlier work of ours (see [8] for details).…”
Section: Some Transcendental Prerequisitesmentioning
confidence: 99%