2017 IEEE International Interconnect Technology Conference (IITC) 2017
DOI: 10.1109/iitc-amc.2017.7968951
|View full text |Cite
|
Sign up to set email alerts
|

Transistors on two-dimensional semiconductors: contact resistance limited by the contact edges

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1

Citation Types

1
10
0

Year Published

2020
2020
2024
2024

Publication Types

Select...
5
1

Relationship

0
6

Authors

Journals

citations
Cited by 7 publications
(11 citation statements)
references
References 6 publications
1
10
0
Order By: Relevance
“…3a shows that Ion (@ ns = 10 13 cm -2 ) does not degrade as Lcont is scaled down to 13nm. This agrees with TCAD simulations 10,17,18 that predict contact edge injection of carriers for 1-3 layers of MoS2 channel. This observation holds true for three different Lch (30 nm, 100 nm, nm) over a wide range of Lcont (500nm to 13nm) and for varying lateral field (VDS = 0.05 V, V).…”
Section: B Contact Length Scalingsupporting
confidence: 87%
“…3a shows that Ion (@ ns = 10 13 cm -2 ) does not degrade as Lcont is scaled down to 13nm. This agrees with TCAD simulations 10,17,18 that predict contact edge injection of carriers for 1-3 layers of MoS2 channel. This observation holds true for three different Lch (30 nm, 100 nm, nm) over a wide range of Lcont (500nm to 13nm) and for varying lateral field (VDS = 0.05 V, V).…”
Section: B Contact Length Scalingsupporting
confidence: 87%
“…To verify such prediction, τ RC is calculated as τ RC = R L × C , where R L is the load resistance and C is junction capacitances of p-i-n diode. We use the following formula, to calculate the value of C , where ε is the in-plane dielectric constant (8.5), k is the electrostatic force constant (8.99 × 10 9 N·m 2 /C 2 ), W and L represent the width and length of WSe 2 channel, respectively. C is calculated to be about 6 × 10 –6 pF.…”
Section: Resultsmentioning
confidence: 99%
“…However, the doping still improves the contact resistance by thinning the SB even though it cannot affect the metal−semiconductor interface under the contacts. 32,42,66,67 This apparent contradiction can be explained by a two-path current injection model at the contacts, which is essential to understanding SCTD. 66−68 One path injects carriers vertically from the metal to the semiconductor under the contact, which is therefore largely unaffected by the channel doping.…”
mentioning
confidence: 99%
“…This second path can comprise a significant or even dominant portion of the total carrier injection for thin semiconductor channels. 66,67 It is this mechanism that produces the contact resistance and doping response seen in devices with no doping in the contact regions.…”
mentioning
confidence: 99%
See 1 more Smart Citation