Pd and Ti/RuO2, has been determined from the anodic oxidation (AO) treatment of 2 dm3 of methyl orange azo dye solutions in 0.050 mol dm−3 Na2SO4 of pH 7.0 at constant current density. The anodes were synthesized by the dip-coating method using the corresponding metallic chlorides in isopropanol/water and their morphology, surface roughness, crystallographic structure and composition were analyzed. A mixture of IrO2,Pb2O3 and Pb3O4 were the components in the outperforming Ti/Ir-Pb anode. The effect of current density, Na2SO4 concentration, and cathode nature on the decolorization of azo dye solutions by AO with Ti/RuO2 was examined. Under favorable conditions, 96%-98% color removal was achieved using Ti/Ir-Pb, Ti/Ir-Sn and Ti/Ru-Pb, with lower decolorization for Ti/Pt-Pd and Ti/RuO2 anodes. In all cases, a pseudo-firstorder decolorization process was found. The oxidation ability of anodes rose in the order Ti/RuO2 < Ti/Pt-Pd < Ti/Ru-Pb < Ti/Ir-Sn < Ti/Ir-Pb, achieving 76.0% mineralization for the latter electrode. The mixture of active and non-active materials then gave rise to anodes with higher oxidation power than those made solely of active materials, due to the enhancement of the oxidation action of hydroxyl radicals formed in the non-active oxide. The superiority of Ir over Ru in the mixed metal oxides was related to the greater adsorption of organics on its surface, thereby favoring their oxidation. Ammonium and sulfate ions were released as pre-eminent ion. Stable byproducts and final short-linear aliphatic carboxylic acids were identified by gas chromatography-mass spectrometry and ion-exclusion high-performance liquid chromatography. Based on these compounds, a reaction sequence for methyl orange mineralization is proposed.