“…14) is given by [D , D ′ ] 11 = n,r,r m,s,s [ D n | (2r,2r) , D ′ m | (2s,2s) ] | (2(r+s),2(r+s)) , (A.1a) [D , D ′ ] 21 = n,r,r m,s,s[ D n | (2r,2r) , D ′ m | (2s,2s) ] | (2(r+s−1),2(r+s)) , (A.1b) [D , D ′ ] 12 = n,r,r m,s,s [ D n | (2r,2r) , D ′ m | (2s,2s) ] | (2(r+s),2(r+s−1)) , (A.1c) [D , D ′ ] 22 = n,r,r m,s,s [ D n | (2r,2r) , D m | (2s,2s) ] | (2(r+s−1),2(r+s−1)) , (A.1d) for coderivations D = n,r,r D n | (2r,2r) andD ′ = m,s,s D ′ m | (2s,2s) . An alternative expressions obtained by projecting the intermediate state[24],[ D , D ′ ] 11 = n D n π (0,0) 1 D ′ ∧ I n−1 − (−) |D||D ′ | D ′ n π (0,0) ∧ I n−1 , (A.2a) [ D , D ′ ] 21 = n ′ ∧ I n−1 − (−) |D||D ′ | D ′ n π ′ ∧ I n−1 − (−) |D||D ′ | D ′ n π ′ ∧ I n−1 − (−) |D||D ′ | D ′ n π ∧ I n−1 , (A.2d)are also useful. Here, |D| (|D ′ |) is equal to 0 or 1 when the degree of coderivation D (D ′ ) is even or odd, respectively.…”