“…[44][45] When the same reaction was performed at room temperature, it produced an insoluble solid in nearly quantitative yield; the product appeared to be a monomer and/or oligomers of Pd1-C1 = 1.980(2), Pd1-S1 = 2.2967 (7), Pd1-S2 = 2.3151 (7), Pd1-Cl1 = 2.3961 (7), C1-Pd1-S1 = 83.11(6), C1-Pd1-S2 = 84.46(6), S1-Pd1-Cl1 = 96.27(3), S2-Pd1-Cl1 = 96.12(2), Pd1-S1-C2 = 99.24 (7), Pd1-S1-C4 = 105.61 (7), C2-S1-C4 = 104.64(10), Pd1-S2-C3 = 97.67 (7), Pd1-S2-C5 = 102.18 (7), C3-S2-C5 = 100.81(11), C1-Pd1-S1-C2 = 25.12 (10) by HCl followed by E1 elimination similar to that described above occurs again to give 4 and a mononuclear palladium thiolate, [Pd(SCH 2 CO 2 Me) 2 ], which then aggregates to construct a stable tiara-like octanuclear architecture. Although the above mechanism explains the formation of 1, the bidentate coordination of 2 to PdCl 2 without aromatic C(sp 2 )-H bond activation 45 and the subsequent stepwise elimination of the thiolate groups, similar to the above mechanism, can proceed concurrently to form 1. 39 In this reaction, we presume that the formation of the hexanuclear tiara ring with carboxylic acids as substituents occurred first, and ester condensation between the carboxylic acid moieties and MeOH followed.…”