2019
DOI: 10.1103/physrevb.99.075125
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Tuning of the Ru4+ ground-state orbital population in the 4d4 Mott insulator C

Abstract: The ground-state orbital occupancy of the Ru 4+ ion in Ca2−xLaxRuO4 [x = 0, 0.05(1), 0.07(1) and 0.12(1)] was investigated by performing X-ray absorption spectroscopy (XAS) in the vicinity of the O K edge as a function of angle between the incident beam and the surface of the single-crystal samples. A minimal model of the hybridization between the O 2p states probed at the K edge and the Ru 4d orbitals was used to analyze the XAS data, allowing the ratio of hole occupancies nxy/nyz,zx to be determined as a fun… Show more

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Cited by 13 publications
(13 citation statements)
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“…24, 26, and 27 the spin model is highly anisotropic, with the suggested values of thê z (x) axis anisotropy being equal to = 5.6J (γ = 0.25J), respectively, with J = 5.6 meV reproducing the spin wave dispersion observed in the inelastic neutron scattering experiment 24,26,27 . We note that such a large spin anisotropy originates in the large spin-orbit coupling on the ruthenium ions which, however, is quite widely considered as not strong enough to stabilise the S = 0 ground state 21,24,26,30,32 . Although the latter result can naively be understood as a consequence of the crystal field splitting (between the xz, yz and the xy orbitals) being about twice larger than the spin-orbit coupling 30 and therefore the spin S = 0 states having considerably higher energy than the spin S = 1 states, see Fig.…”
mentioning
confidence: 92%
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“…24, 26, and 27 the spin model is highly anisotropic, with the suggested values of thê z (x) axis anisotropy being equal to = 5.6J (γ = 0.25J), respectively, with J = 5.6 meV reproducing the spin wave dispersion observed in the inelastic neutron scattering experiment 24,26,27 . We note that such a large spin anisotropy originates in the large spin-orbit coupling on the ruthenium ions which, however, is quite widely considered as not strong enough to stabilise the S = 0 ground state 21,24,26,30,32 . Although the latter result can naively be understood as a consequence of the crystal field splitting (between the xz, yz and the xy orbitals) being about twice larger than the spin-orbit coupling 30 and therefore the spin S = 0 states having considerably higher energy than the spin S = 1 states, see Fig.…”
mentioning
confidence: 92%
“…To investigate this rather general problem, we take a closer look at one of the intensively investigated transition metal oxides-Ca 2 RuO 4 19-33 which is a spin S = 1 antiferromagnetically ordered 21,24,26,30,32 and Mott insulating analogue of the unconventional superconductor Sr 2 RuO 4 34 . The other reason for choosing this system is that recently its detailed photoemission spectrum was not only studied experimentally but also successfully modelled using a multiband Hubbard model 28 .…”
mentioning
confidence: 99%
“…Consequently, the xy orbitals are fully populated, leading to the insulating state. Any elongation of the c-axis induced by uni-axial pressure 54 or chemical doping 19,30,31,55,56 leads a transition to a metallic state in which the xy orbitals are only partially occupied. The octahedral flattening also stabilizes magnetic order, both FM and AFM, by increasing DOS at the Fermi level for the former and shifting nesting vector through orbital polarization for the latter.…”
Section: Discussionmentioning
confidence: 99%
“…In this fashion, we probe the two unoccupied t 2g states. This indirect approach has routinely been applied to different TM oxides [21][22][23][24].…”
Section: Introductionmentioning
confidence: 99%