2014
DOI: 10.2140/pjm.2014.269.433
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Twisted Alexander polynomials of 2-bridge knots for parabolic representations

Abstract: Abstract. In this paper we show that the twisted Alexander polynomial associated to a parabolic representation determines fiberedness and genus of a wide class of 2-bridge knots. As a corollary we give an affirmative answer to a conjecture of Dunfield, Friedl and Jackson for infinitely many hyperbolic knots.

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Cited by 21 publications
(11 citation statements)
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“…By [MT,Section 2], the assignment (2.1) gives a non-abelian representation ρ : π 1 (K) → SL 2 (C) if and only if (M, y) ∈ C * × C satisfies the equation…”
Section: Knot Groupsmentioning
confidence: 99%
“…By [MT,Section 2], the assignment (2.1) gives a non-abelian representation ρ : π 1 (K) → SL 2 (C) if and only if (M, y) ∈ C * × C satisfies the equation…”
Section: Knot Groupsmentioning
confidence: 99%
“…From the proof of Theorem 2, one can easily see that the twisted Alexander polynomial associated to any parabolic SL 2 (C)-representation of the knot group of the m-twist knot K m , m > 0, determines the fiberedness and genus of K m . This gives another proof of [MT, Theorem 1.1] and hence of a conjecture of Dunfield, Friedl and Jackson [DFJ] for K m .…”
mentioning
confidence: 73%
“…For a hyperbolic knot K, the holonomy representationρ 0 : Recently, the third author confirmed the conjecture for twist knots [32], and the third author and Tran did for a certain wider class of 2-bridge knots [33]. These are the first infinite families of knots where Conjecture 2.3 is verified.…”
Section: 3mentioning
confidence: 83%