2009
DOI: 10.5802/aif.2498
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Twisted spherical means in annular regions in \mathbb{C}^n and support theorems

Abstract: Let Z(Ann(r, R)) be the class of all continuous functions f on the annulus Ann(r, R) in C n with twisted spherical mean f × µ s (z) = 0, whenever z ∈ C n and s > 0 satisfy the condition that the sphere S s (z) ⊆ Ann(r, R) and ball B r (0) ⊆ B s (z). In this paper, we give a characterization for functions in Z(Ann(r, R)) in terms of their spherical harmonic coefficients. We also prove support theorems for the twisted spherical means in C n which improve some of the earlier results.

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Cited by 5 publications
(9 citation statements)
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“…In this section, we prove Theorem 1.4, which is an analogue of the author's support theorem ([13], Therorem 1.2) for the TSM to the WTSM on C n . Our previous result ( [13], Theorem 1.2) is a special case of Theorem 1.4, when for p = q = 0. We would like to quote support theorem for the case n = 1.…”
Section: Support Theorems For the Weighted Spherical Meansmentioning
confidence: 80%
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“…In this section, we prove Theorem 1.4, which is an analogue of the author's support theorem ([13], Therorem 1.2) for the TSM to the WTSM on C n . Our previous result ( [13], Theorem 1.2) is a special case of Theorem 1.4, when for p = q = 0. We would like to quote support theorem for the case n = 1.…”
Section: Support Theorems For the Weighted Spherical Meansmentioning
confidence: 80%
“…P 1 (Ã)ϕ n−1 k (z) = (−2) −p−q P 1 (z)ϕ n+p+q−1 k−q (z), moreover P 1 (Ã) is right invariant, therefore it follows that P 1 (Ã)(ãP s,t × ϕ n−1 k )(z) = 0, ∀ k ≥ q and |z| = R.Using Hecke-Bochner identity (Lemma 2.2), we getã, ϕ n+s+t−1 k−s P 1 (Ã)P s,t ϕ n+s+t−1 k−s (z) = 0, ∀ k ≥ max(q, s) and |z| = R. Ifà * (P s,t ϕ n+s+t−1 k−s )(R) = 0 for some k ≥ max(q, s), then a computation similar as done for Z * j f in[13], p.2516-17, we havẽ |z| = R and γ = n + s + t. Since {P s,t | S 2n−1 : s, t ≥ 0} form an orthonormal basis for L 2 (S 2n−1 ). An inductive process, then gives the coefficient of highest degree polynomial P p+s,q+t as1 1 k−s (R) = 0.…”
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confidence: 94%
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