2014
DOI: 10.1007/s10878-014-9792-3
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Two cases of polynomial-time solvability for the coloring problem

Abstract: The complexity of the coloring problem is known for all hereditary classes defined by two connected 5-vertex forbidden induced subgraphs except 13 cases. We update this result by proving polynomial-time solvability of the problem for two of the mentioned 13 classes.

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Cited by 29 publications
(14 citation statements)
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“…">11.The class of (4P1,2P1+P3¯)‐free graphs has bounded clique width , hence we apply Theorem (i). 12.This was proved by Malyshev for (P5,C4) and by Malyshev for (P5,2P1+P3¯).…”
Section: Results and Open Problems For (H1h2)‐free Graphsmentioning
confidence: 65%
See 2 more Smart Citations
“…">11.The class of (4P1,2P1+P3¯)‐free graphs has bounded clique width , hence we apply Theorem (i). 12.This was proved by Malyshev for (P5,C4) and by Malyshev for (P5,2P1+P3¯).…”
Section: Results and Open Problems For (H1h2)‐free Graphsmentioning
confidence: 65%
“…">1.This follows from Theorem (i). 2.This was proved by Malyshev for (K1,3,C3)‐free graphs and (K1,3,P5)‐free graphs and by Malyshev for (K1,3,C3++)‐free graphs. 3.First we consider the case when H1 is a forest on at most six vertices not isomorphic to K 1, 5 and H2iC3.…”
Section: Results and Open Problems For (H1h2)‐free Graphsmentioning
confidence: 90%
See 1 more Smart Citation
“…Both polynomial‐time and sans-serif𝖭𝖯‐completeness results are known for (H1,H2)‐free graphs, as shown by many teams of researchers (see e.g. ), but the complexity classification is far from complete: even if we forbid two graphs H1 and H2 of up to four vertices, there are still three open cases left, namely when (H1,H2){(K1,3,4P1),(K1,3,2P1+P2),(C4,4P1)}; see (the graph K1,3 is the claw and C4 is the 4‐vertex cycle). We refer to [18, Theorem 21] for a summary and to the recent paper , in which the number of missing cases when H1 and H2 are both connected graphs on at most 5 vertices was reduced from 10 to 8.…”
Section: Introductionmentioning
confidence: 99%
“…Recently, the complexity dichotomy of the VC problem for classes of graphs which are defined by two connected five-vertex forbidden induced subgraphs received considerable attention. The VC problem is known to be solvable in polynomial time for: (P 5 , gem)-free graphs [1], (P 5 , P 5 )-free graphs [18], (P 5 , P 3 + O 2 )-free graphs [28], (P 5 , P 3 + P 2 )-free graphs [29], and for (P 5 , K 5 − e)-free graphs [29]. In particular, the complexity dichotomy of the VC problem is known for classes of graphs which are defined by two connected five-vertex forbidden induced subgraphs except for the following seven cases: (fork, bull)-free graphs, and (P 5 , H)-free graphs, where H ∈ {K 3 + O 2 , K 2,3 , dart, banner, bull, 2P 2 + P 1 }.…”
Section: Introductionmentioning
confidence: 99%