2017
DOI: 10.4134/ckms.c160059
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Two Dimensional Arrays for Alexander Polynomials of Torus Knots

Abstract: Abstract. Given a pair p, q of relative prime positive integers, we have uniquely determined positive integers x, y, u and v such that vx − uy = 1, p = x + y and q = u + v. Using this property, we show that 1≤i≤x,1≤j≤vis the Alexander polynomial ∆p,q(t) of a torus knot t(p, q). Hence the number Np,q of non-zero terms of ∆p,q(t) is equal to vx + uy = 2vx − 1.Owing to well known results in knot Floer homology theory, our expanding formula of the Alexander polynomial of a torus knot provides a method of algorithm… Show more

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Cited by 2 publications
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“…Corollary 2.6 in [29] states that the number of non-zero terms in the Alexander polynomial of T p,q is 2vx − 1, where x, y, u, v are unique positive integers such that p = x + y, q = u + v such that vx − uy = 1. Now since T p,q are L-space knots (since positive surgery along torus knots with certain coefficient produces lens space, by [19]), Ozsváth and Szabó showed in [24] that the L-space knots forms a 'staircase' complex and hence each such j for which HFK (K, j) = 0 is of dimension 1 i.e dim F ( HFK (T p,q ) is equal the number of non-zero terms in ∆ p,q , which is 2vx − 1.…”
Section: Proof Of Theoremmentioning
confidence: 99%
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“…Corollary 2.6 in [29] states that the number of non-zero terms in the Alexander polynomial of T p,q is 2vx − 1, where x, y, u, v are unique positive integers such that p = x + y, q = u + v such that vx − uy = 1. Now since T p,q are L-space knots (since positive surgery along torus knots with certain coefficient produces lens space, by [19]), Ozsváth and Szabó showed in [24] that the L-space knots forms a 'staircase' complex and hence each such j for which HFK (K, j) = 0 is of dimension 1 i.e dim F ( HFK (T p,q ) is equal the number of non-zero terms in ∆ p,q , which is 2vx − 1.…”
Section: Proof Of Theoremmentioning
confidence: 99%
“…Now comparing gr(a ⊗ ξ 2 ) and gr(b ⊗ µ 1 ), we get that Equality (3) happens iff vx = −1. Now dim( HF K(S 3 , T p,q )) = 2vx − 1 ≥ 3 (see [29,Corollary 2.6]). That implies that vx should be greater than or equal to 2.…”
Section: Proof Of Theoremmentioning
confidence: 99%