“…Assume that f (t, x) = sin x(t) Ax(t) = 9 100 e −t x(t) , t ∈ N12 0 , [t 0, T ] = [0, 3]∪[3, 6]∪[6, 9]∪[9,12],x(0) = 1 , ν k = 1 , t kl = 3 * k , k = 0, 1, 2, 3 , then N = 4 , L = M 1 = 0.100 , M A = 0.090. And by Mathematica software, we know N k=2 H ν (k−2) t (k−1)l , t (k−2)l = 4.476,andsup t∈N T a H ν (N −1) t, t (N −1)l = 1.096, t ∈ N 12 9 ,then M = 4.476 + 1.096 = 5.572 satisfying 0 < M < M −1 A , and we can have(M A + L) N k=2 H ν (k−2) t (k−1)l , t (k−2)l = 0.850admitting the inequality (3.5).…”