2001
DOI: 10.1103/physreva.63.051602
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Understanding the production of dual Bose-Einstein condensation with sympathetic cooling

Abstract: We show, both experimentally and theoretically, that sympathetic cooling of 87 Rb atoms in the |F = 2, m F = 2 state by evaporatively cooled atoms in the |F = 1, m F = −1 state can be precisely controlled to produce dual or single condensate in either state. We also study the thermalization rate between two species. Our model renders a quantitative account of the observed role of the overlap between the two clouds and points out that sympathetic cooling becomes inefficient when the masses are very different. O… Show more

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Cited by 65 publications
(92 citation statements)
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“…For the Boltzmann regime, an analytical formula for the evolution of the temperatures in a mixture of equal mass atoms was derived in Ref. [16]. In the same paper, the approach is extended towards atoms with different mass, however, the dependence of the cooling efficiency on the mass ratio is derived under the assumption of equal trap frequencies.…”
Section: Sympathetic Coolingmentioning
confidence: 99%
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“…For the Boltzmann regime, an analytical formula for the evolution of the temperatures in a mixture of equal mass atoms was derived in Ref. [16]. In the same paper, the approach is extended towards atoms with different mass, however, the dependence of the cooling efficiency on the mass ratio is derived under the assumption of equal trap frequencies.…”
Section: Sympathetic Coolingmentioning
confidence: 99%
“…Below, we adapt the approach of Ref. [16] by assuming an explicit trap potential, so that our results remain valid for large mass ratios. The average energy transfer per collision can be calculated from simple kinematics,…”
Section: Sympathetic Coolingmentioning
confidence: 99%
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“…The cross-species collision cross section can be extracted from the thermalization speed using the following model [28]. In the case of unequal collision partners about 2.7/ξ collisions per atom are needed for thermalization of a gas, γ thm = ξγ coll /2.7.…”
mentioning
confidence: 99%