2012
DOI: 10.1016/j.tcs.2011.10.005
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Updating the complexity status of coloring graphs without a fixed induced linear forest

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Cited by 55 publications
(84 citation statements)
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“…A result which was generalized by Broersma et al [3] who showed that 3-Precoloring Extension can be solved in polynomial time for P 6 -free graphs. Later, Broersma et al [4] extended this result by showing that 3-Precoloring Extension can be solved in polynomial time for H-free graphs if H is a linear forest on at most 6 vertices. The proof methods of both papers [3,4] can directly be applied to show exactly the same results for List 3-Coloring.…”
Section: Theorem 1 ([15])mentioning
confidence: 98%
See 1 more Smart Citation
“…A result which was generalized by Broersma et al [3] who showed that 3-Precoloring Extension can be solved in polynomial time for P 6 -free graphs. Later, Broersma et al [4] extended this result by showing that 3-Precoloring Extension can be solved in polynomial time for H-free graphs if H is a linear forest on at most 6 vertices. The proof methods of both papers [3,4] can directly be applied to show exactly the same results for List 3-Coloring.…”
Section: Theorem 1 ([15])mentioning
confidence: 98%
“…It is known that 4-Coloring is NP-complete for P 8 -free graphs [4] and that 6-Coloring is NP-complete for P 7 -free graphs [3]. On the contrary, Randerath and Schiermeyer [20] showed that 3-Coloring can be solved in polynomial time for P 6 -free graphs.…”
Section: Theorem 1 ([15])mentioning
confidence: 99%
“…This shows Case (ii):5, whereas we obtain Case (ii):4 by using the same arguments together with a result of Král' et al [24], who showed that for any fixed graph H 2 , Coloring is polynomialtime solvable on (C 3 , H 2 )-free graphs if and only if it is so for (C + 3 , H 2 )-free graphs. Case (ii):3 is proven by combining the latter result with corresponding results of Dabrowski, Lozin, Raman and Ries [11] for (C 3 , H 2 )-free graphs that are obtained by combining a number of new results with known results for H 2 = K 1,4 [24], H 2 = S 1,2,2 [32], H 2 = P 2 + P 4 [6], H 2 = 2P 3 [7], H 2 = P 6 [3], H 2 is the cross [33] (the graph obtained from K 1,4 by making a new vertex adjacent to one of its leafs) and H 2 is the 'H'-graph [32] (the graph obtained from K 1,3 by making two new non-adjacent vertices adjacent to the same leaf). Finally, Case (ii):8 has been shown by Dabrowski, Golovach and Paulusma [10].…”
Section: Related Workmentioning
confidence: 83%
“…Then we may assume without loss of generality that d G (u) ≥ k for all u ∈ V (G), as otherwise we perform the following well-known procedure (see e.g. [5]). We repeatedly delete a vertex with degree at most k − 1 from G until no such vertex remains.…”
Section: Case 1 H Has No Dominating Vertexmentioning
confidence: 99%
“…The latter follows from the fact that there exist combinations of integers k and linear forests H for which the k-Coloring problem for H-free graphs is NP-complete; for example, it is known that 4-Coloring is NP-complete for P 8 -free graphs [5] and that 6-Coloring is NP-complete for P 7 -free graphs [4]. Only very few parameterized results for Coloring on H-free graphs are known.…”
Section: Introductionmentioning
confidence: 99%