We study the Short-and-Sparse (SaS) deconvolution problem of recovering a short signal a0 and a sparse signal x0 from their convolution. We propose a method based on nonconvex optimization, which under certain conditions recovers the target short and sparse signals, up to a signed shift symmetry which is intrinsic to this model. This symmetry plays a central role in shaping the optimization landscape for deconvolution. We give a regional analysis, which characterizes this landscape geometrically, on a union of subspaces. Our geometric characterization holds when the length-p0 short signal a0 has shift coherence µ, and x0 follows a random sparsity model with sparsity rate θ ∈ c 1 p 0 ,Based on this geometry, we give a provable method that successfully solves SaS deconvolution with high probability.Because of this symmetry, we only expect to recover a 0 and x 0 up to a signed shift (see Figure 1). Our problem of interest can be stated more formally as: Problem 1.1 (Short-and-Sparse Deconvolution). Given the cyclic convolution y = a 0 * x 0 ∈ R n of a 0 ∈ R p0 short (p 0 n), and x 0 ∈ R n sparse, recover a 0 and x 0 , up to a scaled shift.Despite a long history and many applications, until recently very little algorithmic theory was available for SaS deconvolution. Much of this difficulty can be attributed to the scale-shift symmetry: natural convex relaxations fail, and nonconvex formulations exhibit a complicated optimization landscape, with many 1 arXiv:1901.00256v2 [eess.SP] 11 Apr 2019 ϕ ρ is strongly convex in this region, and it has a minimizer very close to s [a 0 ].Geometry near a single shift. To gain intuition into the properties of ϕ ρ , we first visualize this function in the vicinity of a single shift s [a 0 ] of the ground truth a 0 . In Figure 3, we plot the function value of ϕ ρ overwhere B 2 ,r (a) is a ball of radius r around a. We make two observations:• The objective function ϕ ρ is strongly convex on this neighborhood of s [a 0 ].• There is a local minimizer very close to s [a 0 ].Write x 0J = ι * J x 0 and (x 0 ) I\J = P I\J x 0 . We can further notice that