2014
DOI: 10.1007/jhep06(2014)062
|View full text |Cite
|
Sign up to set email alerts
|

Vanishing superconformal indices and the chiral symmetry breaking

Abstract: Superconformal indices of 4d N = 1 SYM theories with SU(N ) and SP(2N ) gauge groups are investigated for N f = N and N f = N + 1 flavors, respectively. These indices vanish for generic values of the flavor fugacities. However, for a singular submanifold of fugacities they behave like the Dirac delta functions and describe the chiral symmetry breaking phenomenon. Similar picture holds for partition functions of 3d supersymmetric field theories with the chiral symmetry breaking.

Help me understand this report
View preprint versions

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

1
40
0

Year Published

2015
2015
2021
2021

Publication Types

Select...
8
1

Relationship

0
9

Authors

Journals

citations
Cited by 30 publications
(41 citation statements)
references
References 62 publications
(167 reference statements)
1
40
0
Order By: Relevance
“…The boundary conditions for the Boltzmann weights play a role of the "chiral" symmetry breaking phenomenon on the gauge theory side [6,80]. It is not well-studied subject on the level of supersymmetric partition functions and much work remains to be done in this direction.…”
Section: 3mentioning
confidence: 99%
“…The boundary conditions for the Boltzmann weights play a role of the "chiral" symmetry breaking phenomenon on the gauge theory side [6,80]. It is not well-studied subject on the level of supersymmetric partition functions and much work remains to be done in this direction.…”
Section: 3mentioning
confidence: 99%
“…This is a consequence of confinement and chiral symmetry breaking [36,37]. At low energies the theory on the left-hand side is described by the mesons and the baryons.…”
Section: Quiver Gauge Theories and Their Supersymmetric Indicesmentioning
confidence: 99%
“…If we give vevs to baryons of fugacities (α The theory has a vacuum where M = Λ 2 and B =B = 0, which would precisely Higgs the left and right SU(N ) 2 gauge groups and thus bring us back to the standard theory with two fewer minimal punctures, except for the extra baryonic degrees of freedom B,B. Even at the level of the index, one finds that the N f = N node effectively produces a delta function [36] of the fugacities of the left and right SU(N ) z 2 gauge groups, multiplied by the index of the baryons B,B with fugacities (α…”
Section: Jhep07(2015)073mentioning
confidence: 99%