Viscosity of binary liquid mixtures

1.1 μm Superficially porous particles for liquid chromatography

“…[26] The viscosity of the acetone:methanol mixture was calculated based on a plot of viscosity versus mole fraction of acetone. [27] The viscosity of the hexane:isopropanol and acetone:isopropanol were calculated based on plots constructed from tabular values of viscosity and mole fraction. [28] The following constants were used based on literature values and calculations based on measured particle characteristics: skel = 2.1, ε = 0.21, ε f = 0.21, p = 0.00113, and K 2 = 5.4 [20,21].…”

Vitrification, relaxation and free volume in glycerol–water binary liquid mixture: Spin probe ESR studies

“…Thermodynamic, transport and relaxation properties of binary liquid mixtures have been the subject of scientific investigation for the last few decades. The presence of two different masses and length scales of interactions is largely responsible for the composition dependence -often non-linear as suggested by experiments [1,2] and theoretical studies [3,4] -of static and dynamic properties of such systems. Nevertheless, the tunability offered by this composition dependence of certain properties is of great use in both industrial and laboratory chemistry and biology.…”

Chemical Locomotives Based on Polymer Supported Catalytic Nanoparticles

“…Since the dimensions of the bead and the bubble together are much less than that of the liquid in the container, the later can be assumed to be infinite in extent so that the edge effects can safely be neglected and that the viscous drag can be calculated using Stokes formula, F v = 6πη rv , where we have approximated Furthermore, viscosity of a binary liquid mixture can roughly be estimated from the empirical expression, η = x 1 2 η 1 + x 2 2 η 2 + x 1 x 2 η‘, where η is the viscosity of the mixture, x i and η i are respectively the mole fraction and viscosity of species i in the mixture and η‘ is a composition independent cross coefficient, nearly equal to η 1 + η 2 . Since the bubble does not get detached from the bead during the motion, we may assume that the force resulting from the excess pressure inside the gas bubble F P , is balanced by the capillary force F C .…”