2003
DOI: 10.1039/b301297b
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Volume of reaction, energetics, and kinetics of tetrahydrothiophene displacement of solvent from Mo(CO)5(alkane)

Abstract: Laser-induced optoacoustic spectroscopy (LIOAS) was used to determine the enthalpies and volumes of reactions for each step in ligand substitution of molybdenum hexacarbonyl with tetrahydrothiophene (THT). The enthalpy for substitution of CO on Mo(CO)6 by an alkane and of coordinated alkane on Mo(CO)5(alkane) by THT are 114 and -99 kJ mol(-1), respectively. Likewise, the volumes of reaction are 13 and -16 ml mol(-1). These results allow the calculation of the bond energies for Mo-alkane (56 kJ mol(-1)) and Mo-… Show more

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Cited by 8 publications
(3 citation statements)
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“… a Values in parentheses are the errors in the last digit(s). b Determination in heptane assuming Δ V 1 = Δ V 2 = 0. c Multisolvent determination like that shown in Figure . d The relative errors for BE (bond energy) are the same as the errors for Δ H 2 : BE(M-L) = BE(M-CO) – Δ H 1avg – Δ H 2 . e Tetrahydrofuran, ref . f Tetrahydrothiophene, ref . …”
Section: Resultsmentioning
confidence: 99%
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“… a Values in parentheses are the errors in the last digit(s). b Determination in heptane assuming Δ V 1 = Δ V 2 = 0. c Multisolvent determination like that shown in Figure . d The relative errors for BE (bond energy) are the same as the errors for Δ H 2 : BE(M-L) = BE(M-CO) – Δ H 1avg – Δ H 2 . e Tetrahydrofuran, ref . f Tetrahydrothiophene, ref . …”
Section: Resultsmentioning
confidence: 99%
“…The fractional amplitude for the slow component of the signal likewise can be expressed (eqs and ). A series of linear alkanes were used to vary the solvent thermoelastic properties, and the calculations assume that the metal–solvent bond energy does not vary significantly for the different alkane chain lengths. , normalϕ 1 = h normalν normalχ normalΦ normalΔ H 1 normalχ + normalΦ normalΔ V 1 h normalν normalχ h normalν normalχ false( 1 normalϕ 1 false) normalΦ = normalΔ H 1 normalχ normalΔ V 1 normalϕ 2 = normalΦ false( normalΔ H 2 normalχ normalΔ V 2 false) h normalν normalχ h normalν normalχ normalϕ 2 normalΦ = normalΔ H 2 normalχ normalΔ V 2 …”
Section: Methodsmentioning
confidence: 99%
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