2005
DOI: 10.1007/s11232-005-0012-2
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Wave functions of the toda chain with boundary interaction

Abstract: In this contribution, we give an integral representation of the wave functions of the quantum N -particle Toda chain with boundary interaction. In the case of the Toda chain with one-boundary interaction, we obtain the wave function by an integral transformation from the wave functions of the open Toda chain. The kernel of this transformation is given explicitly in terms of Γ-functions. The wave function of the Toda chain with two-boundary interaction is obtained from the previous wave functions by an integral… Show more

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Cited by 5 publications
(3 citation statements)
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“…Acting by both sides of this identity on Ψ ρn , fixing λ = λ n,k (i.e. at the zeroes of the eigenvalue polynomial of B n (λ)) and using the inverse of ( 70) with (67), we see that, very similar to A n (λ n,k ), also D n (λ n,k ) acts as a shift operator on Ψ ρn , compare (27):…”
Section: ) (58)mentioning
confidence: 99%
“…Acting by both sides of this identity on Ψ ρn , fixing λ = λ n,k (i.e. at the zeroes of the eigenvalue polynomial of B n (λ)) and using the inverse of ( 70) with (67), we see that, very similar to A n (λ n,k ), also D n (λ n,k ) acts as a shift operator on Ψ ρn , compare (27):…”
Section: ) (58)mentioning
confidence: 99%
“…The integral (3.2) absolutely converges. The proof is identical to that of [9,10]. For instance, we can use an elegant estimate [10, (30)] by N. Iorgov and V.Shadura, which states that for fixed γ n,i = λ i ∈ ıR, i = 1, .…”
Section: Wave Functionmentioning
confidence: 90%
“…Further, again in virtue of the symmetry, in doing so, one may also assume the ordering λ 1 < · · · < λ N . For such an ordering of both sets of variables, one has the identity [15] N k=1…”
Section: A Proof Of Proposition 11mentioning
confidence: 99%