2012
DOI: 10.1016/j.jde.2012.08.005
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Well-posedness of the Cauchy problem for p-evolution equations

Abstract: We consider p-evolution equations in (t,x) with real characteristics. We give sufficient conditions for the well-posedness of the Cauchy problem in Sobolev spaces, in terms of decay estimates of the coefficients as the space variable x goes to infinity

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Cited by 21 publications
(36 citation statements)
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“…In this way, we are able to prove that there exists σ > 0 such that for all s 1 , s 2 ∈ R, f ∈ C([0, T ]; H s 1 ,s 2 (R)) and g ∈ H s 1 ,s 2 (R), there is a unique solution u ∈ C([0, T ]; H s 1 −σ ,s 2 (R)) which satisfies the following energy estimate: (1.18) for some C = C(s 1 , s 2 ) > 0. We do not prove here this alternative result, the proof being a repetition of the one of Theorem 1.1 in [6] in our functional setting. REMARK 1.5.…”
Section: Introductionmentioning
confidence: 87%
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“…In this way, we are able to prove that there exists σ > 0 such that for all s 1 , s 2 ∈ R, f ∈ C([0, T ]; H s 1 ,s 2 (R)) and g ∈ H s 1 ,s 2 (R), there is a unique solution u ∈ C([0, T ]; H s 1 −σ ,s 2 (R)) which satisfies the following energy estimate: (1.18) for some C = C(s 1 , s 2 ) > 0. We do not prove here this alternative result, the proof being a repetition of the one of Theorem 1.1 in [6] in our functional setting. REMARK 1.5.…”
Section: Introductionmentioning
confidence: 87%
“…On the other hand, the assumptions on the coefficients given in our paper are stronger than the ones used in [5,6]. Hence, one can modify the approach and define the functions λ p−k in the following by (2.14) for 1 ≤ k ≤ p − 1 (hence also for k = 1) as in [6] and repeat readily the argument of the proof using the estimates of Lemma 2.1 in [6] instead of Lemma 2.5 in the case k = 1. In this way, we are able to prove that there exists σ > 0 such that for all s 1 , s 2 ∈ R, f ∈ C([0, T ]; H s 1 ,s 2 (R)) and g ∈ H s 1 ,s 2 (R), there is a unique solution u ∈ C([0, T ]; H s 1 −σ ,s 2 (R)) which satisfies the following energy estimate: (1.18) for some C = C(s 1 , s 2 ) > 0.…”
Section: Introductionmentioning
confidence: 90%
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