2005
DOI: 10.1007/s00020-004-1342-4
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Weyl’s Theorem and Perturbations

Abstract: In the present paper we examine the stability of Weyl's theorem under perturbations. We show that if T is an isoloid operator on a Banach space, that satisfies Weyl's theorem, and F is a bounded operator that commutes with T and for which there exists a positive integer n such that F n is finite rank, then T + F obeys Weyl's theorem. Further, we establish that if T is finite-isoloid, then Weyl's theorem is transmitted from T to T + R, for every Riesz operator R commuting with T . Also, we consider an important… Show more

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Cited by 30 publications
(8 citation statements)
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“…This generalizes, and brings under one umbrella, a number of results from [2 3], [7,8], [9,11,13,14], [16], [17], [25,26] and others. such that p(A) = 0; T ∈ B(X) is (algebraically) polynomially PS, T ∈ P(PS), if there exists a non-constant polynomial q(.)…”
Section: Introductionsupporting
confidence: 53%
“…This generalizes, and brings under one umbrella, a number of results from [2 3], [7,8], [9,11,13,14], [16], [17], [25,26] and others. such that p(A) = 0; T ∈ B(X) is (algebraically) polynomially PS, T ∈ P(PS), if there exists a non-constant polynomial q(.)…”
Section: Introductionsupporting
confidence: 53%
“…The perturbation result of Theorem 2.3 holds also if we suppose that K n is finite-dimensional for some n ∈ N, see [13]. The following example shows that, in general, an analogous result to that of Theorem 2.3 does not hold for property (w), even within the class of a-isoloid operators.…”
Section: Theorem 22 (Seementioning
confidence: 69%
“…Proof. Since Browder's theorem holds for T + R by Lemma 2.2 of [12], it suffices to show that π 0 (T + R) = E 0 a (T + R). If T − λ is invertible, then T + R − λ is a Fredholm, and hence λ ∈ E 0 a (T + R).…”
Section: Proof Start By Recalling That σ((mentioning
confidence: 99%
“…λ ∈ σ iso (S)) are eigenvalues of the operator. If S is finitely a-isoloid (i.e., if λ ∈ σ iso a (S) implies λ is a finite multiplicity eigenvalue of S), R ∈ L (X) is a Riesz operator which commutes with S, then S satisfies Weyl's theorem implies S + R satisfies Weyl's theorem [12,Theorem 2.7]. Given Banach space operators A ∈ L (X) and B ∈ L (Y), write…”
Section: Introductionmentioning
confidence: 99%