“…We cannot always have such a semidirect product being an I-E group since dihedral groups of order 2/j are not 7-is when n is even by [3], but what about when the factors have relatively prime orders? In the next section, we shall show that if G is the semidirect product of a normal 7-E group H and an I-E group K with (\H\, \K\) = I, Xhe problem of determining when G is I-E reduces to considering whether one endomorphism lies in 1(G), namely, the projection of G onto K. We then use this result in the third and final section of this paper to prove that the semidirect product of two cyclic groups of relatively prime orders is I-E, thereby eliminating the assumption in [4] that the normal cyclic subgroup is the commutator subgroup. However, after we complete this proof, we shall point out that the cyclic subgroups may be reselected so that they still have relatively prime orders and the normal one is the commutator subgroup.…”