2014
DOI: 10.1007/jhep09(2014)114
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Λ MS ¯ n f = 2 $$ {\varLambda}_{\overline{\mathrm{MS}}}^{\left({n}_f=2\right)} $$ from a momentum space analysis of the quark-antiquark static potential

Abstract: We determine Λ (n f =2) MS by fitting perturbative expressions for the quarkantiquark static potential to lattice results for QCD with n f = 2 dynamical quark flavors. To this end we use the perturbative static potential at the presently best known accuracy, i.e. up to O(α 4 s ), in momentum space. The lattice potential is computed on a fine lattice with a ≈ 0.042 fm in position space. To allow for a comparison and matching of both results, the lattice potential is transformed into momentum space by means of a… Show more

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Cited by 22 publications
(11 citation statements)
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“…Other analyses aiming at extracting Λ MS from the static energy with less than three flavors include Refs. [25,32,33,[37][38][39][40]. In particular, let us mention that the n f = 2 analysis of Ref.…”
Section: Discussion and Comparison With Other Workmentioning
confidence: 99%
“…Other analyses aiming at extracting Λ MS from the static energy with less than three flavors include Refs. [25,32,33,[37][38][39][40]. In particular, let us mention that the n f = 2 analysis of Ref.…”
Section: Discussion and Comparison With Other Workmentioning
confidence: 99%
“…In principle it is beyond purely perturbative reach, as it cannot be 'perturbatively connected' to the more precisely knownΛ 3 value [44]. Our own estimate [22] ofΛ 2 from the pion decay constant gaveΛ 2 ≃ 360 +42 −30 MeV, while some recent lattice determinations areΛ 2 ≃ 330 ± 45 (staggered Wilson fermions [46]) andΛ 2 ≃ 331 ± 21 (quark static potential method [47]). (Incidentally the latter most precise present lattice determination tended to increase the central value ofΛ 2 by ∼ 15 GeV with respect to former similar determinations [48]).…”
Section: Evolution To Higher Energy and Phenomenological Comparisonmentioning
confidence: 98%
“…This raises the question of a suitable running coupling as there is no unique definition of α s beyond two-loop. A quasi-particle picture suggests that an appropriate choice of α s can be deduced from a heavy quark potential [28,29]. An analytic expression for a coupling that generates a linearly rising static quark potential at large distances is given by [30] α s,HQ (z) = 1 β 0…”
mentioning
confidence: 99%