2019
DOI: 10.48550/arxiv.1908.11484
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$Ω$-deuteron Interaction in Folding Model

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Cited by 4 publications
(6 citation statements)
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“…There is another method for few-body system interaction by which the system is not deeply bound, called as the folding model [62,63]. The folding model assumes that nucleus is bound as a molecular state like dibaryonbaryon state.…”
Section: B Solving Three-body Bound Statementioning
confidence: 99%
“…There is another method for few-body system interaction by which the system is not deeply bound, called as the folding model [62,63]. The folding model assumes that nucleus is bound as a molecular state like dibaryonbaryon state.…”
Section: B Solving Three-body Bound Statementioning
confidence: 99%
“…In addition to the femtoscopic studies of hadron-hadron (hh) interactions, the hadron-deuteron (hd) correlation functions can increase our knowledge and understanding about the hadronic many-body system. Correspondingly because of this several exploratory theoretical research of the hd correlation functions are done like pd and hd 10 , K − d 10 , Λd 11 (Actually, the Λd correlation function is on agenda 12 ), Ξd 13 , and very recently production of ΩNN and ΩΩNin ultra-relativistic heavy ion collisions is discussed in 14 also Ωd interaction in a simple folding model studied in 15 . Therefore, precise calculation and derivation of more properties of Ωd bound state system are necessary.…”
Section: Introductionmentioning
confidence: 99%
“…As the next step in the femtoscopic studies of hh interactions, the hadron-deuteron (hd) correlation functions would be promising as discussed in Refs. [29,30]. The hd correlation function has several merits to study.…”
Section: Introductionmentioning
confidence: 99%
“…One of the important issues in the hd correlation function is the large size and the small binding energy of the deuteron. In the previous exploratory theoretical studies of the hd correlation functions, Λd [29] and Ω − d [30], the hd interaction is evaluated using the intrinsic deuteron wave function, but the deuteron is regarded as a point-like inert particle in calculating the correlation function: The source function of the deuteron as a point particle is assumed [29,30]. In addition, a folding potential is adopted and deuteron breakup effects are ignored in Ref.…”
Section: Introductionmentioning
confidence: 99%
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