Trifluoromethyl iodide reacts with [AuMeL] to give [AuMe,(CF,)L] and [AulL] (L = PMe, or PMe,Ph), or [Au-(CF,)L] and Me1 (L = PPh,), or a mixture of these products ( L = PMePh,). In some cases reaction of [AuMe-(PMe,)] with CF,I gives [AuMe(CF,) I (PMe,)].Evidence is presented that the reactions proceed, a t least in part,
L69 3BXby a free-radical chain mechanism.REACTIONS of methyl iodide with the complexes [AuMeL] (L = PMe,, PMePh, PMePh,, or PPh,) have been reported previou~ly.l-~ In all cases the initial reaction took place according to equation (l), the products arising from rapid methyl for halogen exchange between the product of oxidative addition of [AuMeL] with MeI, namely cis-[AuMe,IL] and unchanged [AuMeL] [equation ( 2)]. However, a slower subsequent reaction then took cis-[AuMe,IL] + [AuMeL] place which was dependent on the nature of the ligand L.Thus when L = PPh, the complex [AuMe,L] underwent reductive elimination of ethane to give ultimately the products of equation (3), while when L = PMe, or