No abstract

In the title compound, C16H15BrN2O3, there are two independent mol­ecules (A and B) in the asymmetric unit. The major difference between the two mol­ecules is the dihedral angle formed by the aromatic rings [72.6 (2) and 18.8 (2)° for A and B, respectively]. The benzohydrazide groups are not planar and the mol­ecules exist in trans configurations with respect to the methyl­idene units. The mol­ecular packing is stabilized by two inter­molecular N—H⋯O hydrogen bonds, forming chains parallel to the c axis. Only the A mol­ecules of the asymmetric unit are held together by π–π inter­actions [centroid–centroid distance = 3.714 (3) Å].

The title compound, C14H12N2O3·CH4O, consists of a Schiff base mol­ecule and a methanol mol­ecule of crystallization. The Schiff base mol­ecule is nearly planar, the dihedral angle between the planes of the two benzene rings being 7.2 (2)°. The mol­ecule exists in the trans configuration with respect to the methyl­idene unit. In the crystal structure, the Schiff base and methanol mol­ecules are linked through O—H⋯O, N—H⋯O and O—H⋯N hydrogen bonds, forming a three-dimensional network.

In the title compound, C15H12ClN3O4, the benzohydrazide group is not planar and the mol­ecule exists in a trans configuration with respect to the methyl­idene unit. The dihedral angle between the two substituted benzene rings is 0.4 (3)°. In the crystal structure, mol­ecules are linked by inter­molecular N—H⋯O hydrogen bonds, forming chains parallel to the c axis.