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An integral is defined using the Moore-Smith limit and this new integral is compared to the Henstock integral.It is well-known though not easily found in the literature that the Riemann integral can be defined by Moore-Smith limit using divisions. Then many properties of the Riemann integral will have straightforward proofs. In this paper, we shall investigate whether the Henstock integral can also be defined by means of Moore-Smith limit involving δ-fine divisions. We assume that the reader is familiar with the definition of the Henstock integral [3].A division D of [a, b] is a finite set of interval-point pairs ([u, v], ξ) such that the intervals [u, v] from D are non-overlapping and their union is [a, b] Then D 2 is said to be finer than D 1 in the Riemann sense, or in symbols, D 2 D 1 if for each ([s, t], η) ∈ D 2 we have [s, t] ⊂ [u, v] for some ([u, v], ξ) ∈ D 1 and when [s, t] = [u, v] we have η = ξ. Then (D, ) is a directed set of divisions D of [a, b] . More precisely, the following conditions are satisfied:

For an ordered subset W = {w 1 , w 2 , w 3 ,. .. , w k } of vertices in a connected graph G and a vertex v of G, the metric representation of v with respect to W is the k-vector r(v|W) = (d(v, w 1), d(v, w 2), d(v, w 3),. .. , d(v, w k)). The set W is called a resolving set of G if r(u|W) = r(v|W) implies u = v. The metric dimension of G, denoted by β(G), is the minimum cardinality of a resolving set of G. Let n ≥ 3 be an integer. A truncated wheel, denoted by T W n , is the graph with vertex set V (T W n) = {a} ∪ B ∪ C, where B = {b i : 1 ≤ i ≤ n} and C = {c j,k : 1 ≤ j ≤ n, 1 ≤ k ≤ 2}, and edge set E(T W n) = {ab i : 1 ≤ i ≤ n} ∪ {b i c i,k : 1 ≤ i ≤ n, 1 ≤ k ≤ 2} ∪ {c j,1 c j,2 : 1 ≤ j ≤ n} ∪ {c j,2 c j+1,1 : 1 ≤ j ≤ n}, where c n+1,1 = c 1,1. In this paper, we compute the metric dimension of truncated wheels.