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Had the authors actually omitted the negative values of m from their algorithm, they could not have obtained the results shown in Figs. 1 and 2 (which appear to be correct).3) In the right-hand side (RHS) of (12), it appears that a has been set equal to 0 (i.e., that the original S-transform as defined in [2] is being used). I suggest that the RHS of (12) be changed to e 0[2 m =(aNT +bjnj) ] for consistency with the scaling function used in (4). 4) In step 3 of the list following (13), G[n; m] should be replaced with G[m; n] for consistency with the earlier notation. Similarly, S[n; j] should read S[j; n] in step 6; the indices of S are also reversed in (13). 5)Step 5 of the same list should read "Determine B[n; m] = H[m+n]1G[m; n]," instead of "Determine B(n; m) = H(m+ n) 1 G(m + n)." The quantity G defined in (12) has two arguments. 6) The text following (14) contains Matlab code that should be explained. Here, s is a matrix whose columns denote times and whose rows denote frequencies. Max(s) is a row vector that contains the maxima of the columns of s; max(s 0 ) is a row vector that contains the maxima of the rows of s, and in the definitions of A 2 and A 4 ; min(max(abs(s 0 ))) denotes the smallest number obtained when the maximum absolute value of the S-transform is found at each frequency. 7) The scaling function of (4) is similar to a scaling function defined by [3], viz. (f) = 1=(a + bf). Equation (4) is preferable to the scaling function of [3], because the use of jfj in place of f prevents (f) from becoming infinite at f = 0a=b. It also ensures that the same window is used at f = f 0 and f = 0f 0 (here, f0 is an arbitrary frequency), which is necessary if the S-transform is to be used for time-frequency filtering. REFERENCES[1] M. V. Chilukuri and P. K. Dash, "Multiresolution S-transform-based fuzzy recognition system for power quality events,"The authors would like to thank the discusser for his interest in the paper and valuable comments and suggestions.1) As the discusser correctly pointed out, (7) should be 1 01 S(; f) = H(f):2) The limits of (11) do not need to be changed [2], [3]. However, Fig. 2(c) should be replaced with the following figure, which is obtained by the plotting magnitude of the S-transform matrix. 3) Suggestion (3) can be considered for maintaining consistency of the equations. 4) Suggestion (4) can be considered for maintaining consistency of the equations. 5) The authors apologize for the error in the text after (14). It should be read as A 1 = max(max(abs(s))) with PQ disturbance; A 2 = min(max(abs(s))) with PQ disturbance; B1 = max(max(abs(s))) without PQ disturbance; B 2 = min(max(abs(s))) without PQ disturbance. where max(abs(s)) is a row vector, plotting upon which gives the amplitude versus time plot as shown in Fig. 3(c). Hence, A1 is maxima and A 2 is minima of the amplitude versus time plot with PQ disturbance. Similarly, B1 is maxima and B2 is minima of the amplitude versus time plot without PQ disturbance. 6) As suggested by the discusser, step (5) on page 2 should be...

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