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The extraction and separation of copper(II), zinc(II), cobalt(II), and cadmium(II) were investigated. Both copper(II) and zinc(II) formed ammine-complexes, while cadmium(II) and cobalt(II) formed hydroxide precipitates in an ammonia medium. By the addition of sodium dodecylsulfate (SDS), a copper(II) complex formed an ion-pair (copper-ammine-DS), which was extracted into the SDS phase. However, a zinc(II) complex did not form an ion-pair, and was soluble in water. Copper(II) ion was recovered by stripping (back-extraction) after the addition of hydrochloric acid. This method was applied to the separation of copper(II) in a brass alloy.

Much interest has been devoted to lantern-type dimer complexes with a direct metal-metal bond, due to their unique properties based on the metal-metal bond.1 Recently, lantern-type dimers have been used as building blocks in combination with axial linker ligands to produce assembled complexes with extended 1 -3 dimensional structures. 1 Rhodium(II) formamidinate dimers, [Rh2(4-R-pf)4] (4-R-pf -= N, N¢-bis(4-alkylphenyl) formamidinate anion), were reported to work as building blocks, although rhodium(II) carboxylate dimers ([Rh2(O2CR)4]) are still more common as building blocks. 1-3 1,4-Diisocyanobenzne (1,4-dib) coordinates to the rhodium(II) atoms through the crowded axial sites with four aryl groups of [Rh2(4-R-pf)4], because 1,4-dib has long and narrow coordinating isocyano arms. 2,3 We have reported crystal structures of 1-dimensinal polymer complexes, [Rh2(4-Me-pf)4(1,4-dib)]n·2n(C6H6) and [Rh2(4-Me-pf)4(1,4-dib)]n·2n(toluene), and a hexanuclear complex, [{Rh2(4-Me-pf)4}3(1,4-dib)2]·6H2O. 2,3 Although our attempts to obtain the assembled complexes using axial linkers The title compound of a lantern-type rhodium(II) dimer, [Rh2(4-Et-pf)2(O2CCF3)2(H2O)(MeOH)] (4-Et-pf -= N,N¢-bis(4-ethylphenyl)formamidinate anion), was isolated and the crystal structure was determined by the single-crystal X-ray diffraction method at 90 K. It crystallizes in the triclinic space group P1 with a = 10.866 (2)

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