“…Since m, 2, 2 ( ∼ = Q 4m ), P 24 := 3, 3, 2 , P 48 := 4, 3, 2 and P 120 := 5, 3, 2 are finite groups, by the proof of elliptization conjecture of Perelman, M m, n, k is spherical, i.e., M m, n, k ∼ = S 3 / m, n, k for these groups m, n, k . It is not difficult to prove that, the abelianization of m, n, k ∼ = Z ⊕ H for some group H if and only if (m, n, k) = (6, 3, 2), (4,4,2) or (3,3,3). Therefore, in these three cases, the 3-manifold M m, n, k has a handle and in all the other cases, M m, n, k is handle-free.…”