2010
DOI: 10.1007/s11276-010-0261-3
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A characterization of max–min SIR-balanced power allocation with applications

Abstract: We consider a power-controlled wireless network with an established network topology in which the communication links (transmitter-receiver pairs) are corrupted by the co-channel interference and background noise. We have fairly general power constraints since the vector of transmit powers is confined to belong to an arbitrary convex polytope. The interference is completely determined by a so-called gain matrix. Assuming irreducibility of this gain matrix, we provide an elegant characterization of the maxmin S… Show more

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Cited by 8 publications
(16 citation statements)
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“…0 depends on the Lagrangian multipliers resulting from the power constraints s 2 S (inequality constraints). Note that we must have tðaÞ 6 ¼ 0 since otherwise there would be no positive solution uðaÞ [ 0 to (34), regardless of the choice of V. By Theorem 4 in the appendix, we see that there exists a positive vector uðaÞ satisfying (34) iff qðDðaÞVÞ ¼ qðV T DðaÞÞ\1; which is satisfied due to the second equality in (34) and the existence of es ðaÞ [ 0:…”
Section: Proof Of Propositionmentioning
confidence: 95%
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“…0 depends on the Lagrangian multipliers resulting from the power constraints s 2 S (inequality constraints). Note that we must have tðaÞ 6 ¼ 0 since otherwise there would be no positive solution uðaÞ [ 0 to (34), regardless of the choice of V. By Theorem 4 in the appendix, we see that there exists a positive vector uðaÞ satisfying (34) iff qðDðaÞVÞ ¼ qðV T DðaÞÞ\1; which is satisfied due to the second equality in (34) and the existence of es ðaÞ [ 0:…”
Section: Proof Of Propositionmentioning
confidence: 95%
“…Since, for all a C 2, qðV T DðaÞÞ\1 andpðaÞ ¼ es ðaÞ 2 P þ belongs to a bounded subset of R K þþ ; it follows from the second equality in (34) and Theorem 4 that there exists a constant c 1 [ (0, 1) independent of a such that 1 1=ð1 À qðDðaÞVÞÞ 1=c 1 \ þ 1 for all a C 2. From this and (37), we then have kuðaÞk 1 kZðaÞtðaÞk 1 =c 1 þ kRðaÞtðaÞk 1 : By (27) and (36), the left-hand side is bounded (consider u k (a) for any k 2 B 6 ¼ ;).…”
Section: Proof Of Propositionmentioning
confidence: 98%
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“…Problem (2) has attracted considerable interest in the recent past; see e.g. [4] and references therein.…”
Section: Preliminariesmentioning
confidence: 99%