2018
DOI: 10.1016/j.ejc.2017.07.016
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A faster FPTAS for the Unbounded Knapsack Problem

Abstract: The Unbounded Knapsack Problem (UKP) is a well-known variant of the famous 0-1 Knapsack Problem (0-1 KP). In contrast to 0-1 KP, an arbitrary number of copies of every item can be taken in UKP. Since UKP is NP-hard, fully polynomial time approximation schemes (FPTAS) are of great interest. Such algorithms find a solution arbitrarily close to the optimum OPT(I), i.e. of value at least (1 − ε)OPT(I) for ε > 0, and have a running time polynomial in the input length and

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Cited by 12 publications
(4 citation statements)
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“…The historically first FPTAS for the 1-BKP was given in the seminal work of O. Ibarra and C. Kim [7]. The results of [7] were improved in many ways, for example in the works [2,6,5,8,10,11,12,16,18,19,21]. But, it was shown in [14] (see [13, p. 252] for a simplified proof) that the 2-BKP does not admit an FPTAS unless P = N P .…”
Section: Description Of the Results And Related Workmentioning
confidence: 99%
“…The historically first FPTAS for the 1-BKP was given in the seminal work of O. Ibarra and C. Kim [7]. The results of [7] were improved in many ways, for example in the works [2,6,5,8,10,11,12,16,18,19,21]. But, it was shown in [14] (see [13, p. 252] for a simplified proof) that the 2-BKP does not admit an FPTAS unless P = N P .…”
Section: Description Of the Results And Related Workmentioning
confidence: 99%
“…Intuitively, ABS(p, ρ/6) computes one configuration for each layer, which is added to the solution x in the next step of the algorithm. The above integer program is equivalent to the integer program of the Unbounded Knapsack problem and therefore can be solved approximatively with approximation ratio (1 − ρ/6) in O(|J S,W | + (log(1/ρ)) 3 /ρ 2 ) operations [12]. The algorithm needs at most O(M(ln(M) + ρ −2 )) steps where it calls the ABS(p, ρ/6) exactly |S| times.…”
Section: Lemmamentioning
confidence: 99%
“…The first three constraints (12) to (14) ensure that the y-coordinates are positioned in the right order and that we use exactly the width of the strip. Furthermore, the variables w j for the width between the y-coordinates are defined.…”
Section: Positioning Containers As Well As Large and Vertical Rectanglesmentioning
confidence: 99%
“…FPTASs on several special cases of 0-1 knapsack are also of interest. For the unbounded knapsack problem, where every item has infinitely many copies, Jansen and Kraft [7] obtained an O(n + ( 1 ε ) 2 log 3 1 ε )-time algorithm; the unbounded version can be reduced to 0-1 knapsack with only a logarithmic blowup in the problem size [5]. For the subset sum Kellerer and Pferschy [11] 2004 O(n log 1 ε + ( 1 ε ) 5/2 log 3 1 ε ) (randomized) Rhee [15] 2015…”
Section: Introductionmentioning
confidence: 99%