“…Actually, the results are not comparable. Example 6 describes a case where all the assumptions of Corollary 1 hold but {y ∈ [0, 5] : f (x, y) < 0} is not convex for all x ∈ fix K =[3,4].Vice versa consider the quasiequilibrium problem (2) associated withC = [0, 2], K (x) = {2 − x} and f (x, y) = −1 if x ∈ [0, 2) and y = 2 0 otherwiseThen, fix K = {1}, the assumptions of Theorem 3.1 in[8] are trivially satisfied, but the set{(x, y) ∈ fix K × C : f (x, y) ≥ 0} = {1} × [0, 2) is not closed.More recently, assumption (i ) has been used in[10, Theorem 2.3] in the context of a locally convex topological vector space. Nevertheless, their result requires the closedness and the convexity of the values of K which is both upper and lower semicontinuous, and the convexity of the level set {x ∈ C : f (x, y) ≥ 0}, for each y ∈ C. Take C = [−2, 2], f (x, y) = x 4 − y 4 − 2x 2 + 2y 2 and…”