“…The specific steps are as follows: The first step is calculating all the triangles. The set of triangles in coordinate system XOY of the first frame is shown as Tri = {hij, hik, hil, hig, hjk, hjl, hjg, hkl, hkg, hlg, ijk, ijl, ijg, ikl, ikg, ilg, jkl, jkg, jlg, klg} (15) Due to measurement error, three theoretically collinear reflectors such as BCD and EFG can still form a triangle. The set of triangles in coordinate system X O Y of the second frame is shown as: Tri = {bcd, bce, bc f , bca, bde, bd f , bda, be f , bea, b f a, cde, cd f , cda, ce f , cea, c f a, de f , dea, d f a, e f a} (16) Every triangle symbol in these two sets stores the lengths of the three lines formed by the three reflectors.…”