2000
DOI: 10.1002/1099-0682(200007)2000:7<1509::aid-ejic1509>3.0.co;2-7
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A Potentiometric and (31P,51V) NMR Study of the Aqueous Molybdovanadophosphate System

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Cited by 37 publications
(30 citation statements)
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“…S4, a typical spectrum of HPA‐5 is given, revealing that a solution of HPA‐5 always contains the whole series of HPA‐ n from n = 1 to 5 and phosphoric acid, which is a residue from the synthesis. The number of peaks in the spectrum for every HPA‐ n corresponds with the number of isomers that is for HPA‐1 (H 4 [PVMo 11 O 40 ]) only 1, for HPA‐2 (H 5 [PV 2 Mo 10 O 40 ]) 5, for HPA‐3 (H 6 [PV 3 Mo 9 O 40 ]) 13, and for HPA‐4 (H 7 [PV 4 Mo 8 O 40 ]) 27 isomers .…”
Section: Resultsmentioning
confidence: 99%
“…S4, a typical spectrum of HPA‐5 is given, revealing that a solution of HPA‐5 always contains the whole series of HPA‐ n from n = 1 to 5 and phosphoric acid, which is a residue from the synthesis. The number of peaks in the spectrum for every HPA‐ n corresponds with the number of isomers that is for HPA‐1 (H 4 [PVMo 11 O 40 ]) only 1, for HPA‐2 (H 5 [PV 2 Mo 10 O 40 ]) 5, for HPA‐3 (H 6 [PV 3 Mo 9 O 40 ]) 13, and for HPA‐4 (H 7 [PV 4 Mo 8 O 40 ]) 27 isomers .…”
Section: Resultsmentioning
confidence: 99%
“…The observed overlapping complicates precise determining the content of V V O 2 + ions and individual HP‐anions in modified solutions. All resonances with x ≥ 2 on 31 P spectra contain ‘fine structure’ that is a consequence of existing positional isomerism ,. The prepared HPA solutions can be represented as a mixture of different Keggin HP‐anions, where the excess of V V is present as VO 2 + cations associated with these anions and H z PO 4 (3–z)– .…”
Section: Resultsmentioning
confidence: 99%
“…The Keggin‐type Mo‐V‐P HPA‐ x aqueous solutions are complex equilibrium mixtures, containing HP‐anions [H x –1 PV V x Mo 12– x O 40 ] 4− with integer x values as well as H + and VO 2 + cations . The partially reduced HPA‐ x solutions also contain VO 2+ cations and various mixed valence HP‐anions [H x + m –1 PV IV m V V x – m Mo 12– x O 40 ] 4− = HPAn m with integer x and m values (0 ≤ m ≤ x ).…”
Section: Resultsmentioning
confidence: 99%