1983
DOI: 10.1016/s0304-0208(08)73355-3
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A Survey on Varieties of PG(4, q) and Baer Subplanes of Translation Planes

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Cited by 9 publications
(7 citation statements)
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“…It follows that a line of PG(4, q)\Eoo corresponds to a Baer subline of PG(2, q2) with a point on £~. The converse of each of these results is true, (see [27,Prop. 1]).…”
Section: Preliminary Resultsmentioning
confidence: 86%
See 2 more Smart Citations
“…It follows that a line of PG(4, q)\Eoo corresponds to a Baer subline of PG(2, q2) with a point on £~. The converse of each of these results is true, (see [27,Prop. 1]).…”
Section: Preliminary Resultsmentioning
confidence: 86%
“…Under this representation of PG(2, q2) in PG(4, q), a plane of PG(4, q)\E~ which does not contain any line of S corresponds to a Baer subplane of PG(2, qa) with q + 1 points on g~, (see [27,Prop. 2]).…”
Section: Preliminary Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…A Baer subline M of PG(2, q 2 ) which is not contained in L ∞ corresponds either to a line of PG(4, q) \ Σ ∞ or to a nondegenerate conic (actually, an ellipse) in one of the planes of PG(4, q) \ Σ ∞ meeting Σ ∞ in a spread line, accordingly as M meets L ∞ in one or zero points. Conversely, any line of PG(4, q) \ Σ ∞ represents a Baer subline of PG(2, q 2 ) which has a point on L ∞ (see [21]). …”
Section: Introduction and Preliminary Resultsmentioning
confidence: 99%
“…Proof A plane II in PG(4, q) that meets H in a line not contained in the spread S corresponds to a Baer subplane of the translation plane 7r ( [25]). The points of the corresponding Baer subplane are given by the points of II\H, together with the points corresponding to the q + 1 spread elements that 1I meets.…”
Section: Lemma 2 Let 7r Be a Translation Plane Containing A Thas Maxmentioning
confidence: 99%