“…Thus, one interesting research topic is minimizing the number of bars in a ladder lottery for a given permutation π. This minimization problem on ladder lottery can be solved by counting the number of "inversions" in π [8,10], where a pair (p i , p j ) in π is called an inversion in π if p i > p j and i < j; for example, there are four inversions in the permutation (4,2,1,3), that is, (4, 2), (4, 1), (4,3) and (2,1), and hence the ladder lottery in Fig. 2(a) has the minimum number of bars.…”