1980
DOI: 10.1002/net.3230100207
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An integer linear programming approach to the steiner problem in graphs

Abstract: Consider a connected undirected graph GIN; El with N = S U P, the set of nodes, where P is designated as the set of Steiner points. A weight is associated with each edge ei of the set E. The problem of obtaining a minimal weighted tree which spans the set S of nodes has been termed in literature as the Steiner problem in graphs. A specialized integer programming (set covering) formulation is presented for the problem. The number of constraints in this formulation grows exponentially with the size of the proble… Show more

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Cited by 125 publications
(65 citation statements)
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“…Of particular importance, we show that ifx is integral, then (4c) and (6) can efficiently be separated exactly, which ensures correctness of a branch-and-cut algorithm for formulations (4) and (15), respectively.…”
Section: Separationmentioning
confidence: 83%
“…Of particular importance, we show that ifx is integral, then (4c) and (6) can efficiently be separated exactly, which ensures correctness of a branch-and-cut algorithm for formulations (4) and (15), respectively.…”
Section: Separationmentioning
confidence: 83%
“…For example, the Steiner tree problem --the problem of connecting at minimum cost a subset S of terminals possibly using some Steiner vertices in V~S ~ can be formulated as (IPo(ls)) where (ls)ij= 1 if ideS and 0 otherwise (or, (IS)i= 1 ifieSand 0 otherwise). The formulation (IPo(ls)) is known as the set covering formulation [2 ]. When r~j= k for all ide Vwe obtain the minimum-cost k-edge-conected network design problem.…”
Section: Eeg~(s) (Ij)cs(s)mentioning
confidence: 99%
“…The obvious question left open by [12], that we answer affirmatively in this paper The algorithms in [1,9] are based on the classical undirected cut formulation for Steiner forests [2]. The integrality gap of this relaxation is known to be (2 − 1/k) and the results in [1,9] are therefore tight.…”
Section: Introductionmentioning
confidence: 69%
“…It therefore follows that t must be the responsible terminal forS and henceS ∈ S t . Finally, notice that δ (S) = δ (S) and hence we can increase yS and decrease y S at the same rate without violating any of the constraints of type (2). Continuing this procedure will lead to a symmetric dual y that is feasible for (D).…”
Section: This Implies That Optmentioning
confidence: 97%