2001
DOI: 10.1006/jath.2000.3545
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Approximation Properties and Construction of Hermite Interpolants and Biorthogonal Multiwavelets

Abstract: Multiwavelets are generated from refinable function vectors by using multiresolution analysis. In this paper we investigate the approximation properties of a multivariate refinable function vector associated with a general dilation matrix in terms of both the subdivision operator and the order of sum rules satisfied by the matrix refinement mask. Based on a fact about the sum rules of biorthogonal multiwavelets, a coset by coset (CBC) algorithm is presented to construct biorthogonal multiwavelets with arbitrar… Show more

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Cited by 86 publications
(91 citation statements)
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“…The first investigations of Hermitetype subdivision schemes of degree larger than 1 have been proposed by Merrien [14], Dyn and Levin [8], Zhou [18], Han [9] and Yu [17]. They have given the theory and the tools (through Fourier transforms for the last three) for analyzing the convergence and smoothness of Hermite-type interpolatory schemes.…”
Section: Introductionmentioning
confidence: 99%
“…The first investigations of Hermitetype subdivision schemes of degree larger than 1 have been proposed by Merrien [14], Dyn and Levin [8], Zhou [18], Han [9] and Yu [17]. They have given the theory and the tools (through Fourier transforms for the last three) for analyzing the convergence and smoothness of Hermite-type interpolatory schemes.…”
Section: Introductionmentioning
confidence: 99%
“…Also see [16], [20], [22], [36] for discussion of univariate refinable Hermite interpolants. However, the situation in higher dimensions is more complicated.…”
Section: Motivation and Introductionmentioning
confidence: 99%
“…For convenience, we denote by E [i,j] , E (i) (c) and E (i,j) (q) for the L-elementary matrices in (1), (2) and (3), and call them Types 1, 2 and 3, respectively. Since …”
Section: Propositionmentioning
confidence: 99%
“…If supp(a) < supp(b), then there is q(z) ∈ P + − and b 1 (z) ∈ P − with supp(b 1 ) < supp(a) such that b(z) = q(z)a(z) + b 1 (z). (2) If supp(a) > supp(c), then there is q(z) ∈ P + − and a 1 (z) ∈ P with supp(a 1 ) < supp(b) such that a(z) = c(z)q(z) + a 1 (z). If supp(a) < supp(c), then there is p(z) ∈ P + + and c 1 (z) ∈ P + with supp(c 1 ) < supp(a) such that c(z) = p(z)a(z) + c 1 (z).…”
Section: Lemma 10mentioning
confidence: 99%