1998
DOI: 10.1080/00927879808826274
|View full text |Cite
|
Sign up to set email alerts
|

Armendariz rings and gaussian rings

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1
1

Citation Types

1
146
0
1

Year Published

2000
2000
2022
2022

Publication Types

Select...
4
4

Relationship

0
8

Authors

Journals

citations
Cited by 206 publications
(148 citation statements)
references
References 7 publications
1
146
0
1
Order By: Relevance
“…Then R is clearly a domain (hence Armendariz) and J(R) = pR. But R/J(R) is isomorphic to Mat 2 (Z p ) by the argument in [11,Exercise 2A] Considering Lemma 1.1 (3,5), one may naturally ask whether the converse of Lemma 1.1(5) also holds. But the answer is negative as can be seen by R = U n (A) (n ≥ 2) over a reduced ring A.…”
Section: On Radicals When Factor Rings Are Armendarizmentioning
confidence: 99%
See 2 more Smart Citations
“…Then R is clearly a domain (hence Armendariz) and J(R) = pR. But R/J(R) is isomorphic to Mat 2 (Z p ) by the argument in [11,Exercise 2A] Considering Lemma 1.1 (3,5), one may naturally ask whether the converse of Lemma 1.1(5) also holds. But the answer is negative as can be seen by R = U n (A) (n ≥ 2) over a reduced ring A.…”
Section: On Radicals When Factor Rings Are Armendarizmentioning
confidence: 99%
“…A ring is called Abelian if every idempotent is central. Armendariz rings are Abelian by the proof of [3,Theorem 6] (or [20,Lemma 7]). …”
Section: On Radicals When Factor Rings Are Armendarizmentioning
confidence: 99%
See 1 more Smart Citation
“…Now suppose that R is a left APP-ring and I = Ra 1 + · · · + Ra n is a finitely generated left ideal of R. Proof. Clearly (2) implies (1). Suppose that R is a left APP-ring.…”
Section: Definition 21 a Ring R Is Called A Left App-ring If The Lementioning
confidence: 99%
“…For rings that admit Armendariz or McCoy condition, it was proved in [1] (resp., [12]) that a ring R is Armendariz (resp., McCoy) if and only if R[x] is Armendariz (resp., McCoy). But it is still an open question of whether the polynomial ring over a weak Armendariz ring is weak Armendariz (see [9] …”
Section: Introductionmentioning
confidence: 99%