2015
DOI: 10.1016/j.jmaa.2014.12.003
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Asymptotic approximation for the solution to a semi-linear parabolic problem in a thick junction with the branched structure

Abstract: We consider a semi-linear parabolic problem in a model plane thick fractal junction Ω ε , which is the union of a domain Ω 0 and a lot of joined thin trees situated ε-periodically along some interval on the boundary of Ω 0 . The trees have finite number of branching levels. The following nonlinear Robin boundary conditionε is given on the boundaries of the branches from the i-th branching layer; α i and β i are real parameters. The asymptotic analysis of this problem is made as ε → 0, i.e., when the number of … Show more

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Cited by 20 publications
(17 citation statements)
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“…Studying PDE problems in such complex structures has paramount importance. We refer to the work in and the references therein for the study in multi‐branched structures. Although the importance of optimal control may be at the junctions, we consider the controls on the entire oscillating part from which we can also understand the contribution from each branch at each level.…”
Section: Introductionmentioning
confidence: 92%
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“…Studying PDE problems in such complex structures has paramount importance. We refer to the work in and the references therein for the study in multi‐branched structures. Although the importance of optimal control may be at the junctions, we consider the controls on the entire oscillating part from which we can also understand the contribution from each branch at each level.…”
Section: Introductionmentioning
confidence: 92%
“…To give an appropriate meaning to the weak solution of homogenized problem, let us introduce the function space scriptH. We use the ideas introduced in . We say, a multi‐sheeted function of the form ϕ:={arrayarray{ϕ2,1,ϕ2,2,ϕ2,3,ϕ2,4}ifxnormalΩ2,array{ϕ1,1,ϕ1,2}ifxnormalΩ1;ϕ0,1ifxnormalΩ0,ϕifxnormalΩ belongs to scriptH, if ϕ − ∈ H 1 (Ω − ), for each i = 0,1,2, the functions ϕ i , m ∈ L 2 (0, L ; H 1 ( M i , M i + 1 ) for m = 1,⋯,2 i and on the boundaries (in the sense of trace), they satisfy rightϕ|normalΓ0=ϕ0,1|normalΓ0,ϕ0,1|normalΓ1=ϕ1,1|normalΓ1=ϕ1,2|normalΓ1,rightϕ1,1|normalΓ2…”
Section: Convergence Analysismentioning
confidence: 99%
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